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সমাধান কর :

\((2x + 3)(y - 1) = 14,\;\; (x - 3)(y - 2) = -1\)
\((x - 2)(y - 1) = 3,\;\; (x + 2)(2y - 5) = 15\)
\(x^2 = 7x + 6y,\;\; y^2 = 7y + 6x\)
\(x^2 = 3x + 2y,\;\; y^2 = 3y + 2x\)
\(x + \dfrac{4}{y} = 1,\;\; y + \dfrac{4}{x} = 25\)
\(y + 3 = \dfrac{4}{x},\;\; x - 4 = \dfrac{5}{3y}\)
\(xy - x^2 = 1,\;\; y^2 - xy = 2\)
\(x^2 - xy = 14,\;\; y^2 + xy = 60\)
\(x^2 + y^2 = 25,\;\; xy = 12\)
\(\dfrac{x + y}{x - y} + \dfrac{x - y}{x + y} = \dfrac{10}{3},\;\; x^2 - y^2 = 3\)
\(x^2 + xy + y^2 = 3,\;\; x^2 - xy + y^2 = 7\)
\(2x^2 + 3xy + y^2 = 20,\;\; 5x^2 + 4y^2 = 41\)