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সমাধান কর :

\( 2^x + 3^y = 31 \\ 2^x - 3^y = -23 \)
\( 3^x = 9^y \\ 5^{x - y + 1} = 25^{xy} \)
\( 3^x \cdot 9^y = 81 \\ 2x - y = 8 \)
\( a^x \cdot a^{y + 1} = a^7 \\ a^{2y} \cdot a^{3x + 5} = a^{20} \)
\( 2^x \cdot 3^y = 18 \\ 2^{2x} \cdot 3^y = 36 \)
\( y^x = x^2 \\ x^{2x} = y^4 \;\;(y \ne 1) \)
\( y^x = 4 \\ y^2 = 2^x \)
\( 4^x = 2^y \\ (27)^{xy} = 9^{y + 1} \)
\( 8y^x - y^{2x} = 16 \\ 2^x = y^2 \)